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A 5.0 -kg rock and a $3.0 \times 10^{-4}$ -kg pebble are held near the surface of the earth. (a) Determine the magnitude of the gravitational force exerted on each by the earth. (b) Calculate the magnitude of the acceleration of each object when released.

49$N$$2.9 \times 10^{-3} N$9.80$m / s^{2}$9.80$m / s^{2}$

Physics 101 Mechanics

Chapter 4

Forces and Newton’s Laws of Motion

Newton's Laws of Motion

Applying Newton's Laws

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to complete the magnitude of the gravitational force that acts on the rock and the people. We only have to remember the equation that the suit, the weight force is. He goes to the mass off the object times, the gravitational acceleration. It is for objects that are nearness surface off the earth as they are. Then for the rock. We have that the weight off the wrong Izzy close to five times 9.8, which gives us 49 new terms then for the people we have three times 10 to the minus four times 9.8, which gives us 29 0.4 time stand to the miners for new terms. Now suppose that remove the table So both Iraq and then people will start to fall. What will be the accelerations off the rock and the people in the situation? So we have to use Newton's second law. Newton's second law says that the net force acting on an object is it goes to its mass times acceleration. The net force that is acting on both Iraq and the people is the weight force. Then the weight is the coast to the mass times acceleration but remember that the weight off anything is a cost to the objects. Mass times the gravity and then disease equals to the mess off the object times acceleration. Note that for any object independent off, if it's Iraq people or an elephant, there will be a simplification off the masses and explanation will simply vehicles to the gravity acceleration off 9.8 meters per second squared. And this is not dependent off the objects mass. So both the rock and the people we will accelerate with an acceleration off 9.8 meters per second squared towards this surface off the earth.

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